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571401241 is a prime number
BaseRepresentation
bin100010000011101…
…110010000011001
31110211012012010221
4202003232100121
52132234314431
6132411040041
720105554555
oct4203562031
91424165127
10571401241
112735a5234
1213b440021
13914c4658
1455c60865
153526e111
hex220ee419

571401241 has 2 divisors, whose sum is σ = 571401242. Its totient is φ = 571401240.

The previous prime is 571401211. The next prime is 571401247. The reversal of 571401241 is 142104175.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 571401216 + 25 = 23904^2 + 5^2 .

It is a cyclic number.

It is not a de Polignac number, because 571401241 - 25 = 571401209 is a prime.

It is not a weakly prime, because it can be changed into another prime (571401247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 285700620 + 285700621.

It is an arithmetic number, because the mean of its divisors is an integer number (285700621).

Almost surely, 2571401241 is an apocalyptic number.

It is an amenable number.

571401241 is a deficient number, since it is larger than the sum of its proper divisors (1).

571401241 is an equidigital number, since it uses as much as digits as its factorization.

571401241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1120, while the sum is 25.

The square root of 571401241 is about 23904.0005229250. Note that the first 3 decimals coincide. The cubic root of 571401241 is about 829.8133034384.

Subtracting from 571401241 its sum of digits (25), we obtain a square (571401216 = 239042).

The spelling of 571401241 in words is "five hundred seventy-one million, four hundred one thousand, two hundred forty-one".