Base | Representation |
---|---|
bin | 110101010001011000… |
… | …111110011010010001 |
3 | 12110122101000221200101 |
4 | 311101120332122101 |
5 | 1414121204421213 |
6 | 42135524052401 |
7 | 4063320425143 |
oct | 652130763221 |
9 | 173571027611 |
10 | 57200076433 |
11 | 22292a52045 |
12 | b104234101 |
13 | 5517658996 |
14 | 2aa8a8cc93 |
15 | 174ba30bdd |
hex | d5163e691 |
57200076433 has 8 divisors (see below), whose sum is σ = 57359840256. Its totient is φ = 57040506000.
The previous prime is 57200076379. The next prime is 57200076449. The reversal of 57200076433 is 33467000275.
57200076433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-57200076433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 57200076392 and 57200076401.
It is not an unprimeable number, because it can be changed into a prime (57200076133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 554463 + ... + 649483.
It is an arithmetic number, because the mean of its divisors is an integer number (7169980032).
Almost surely, 257200076433 is an apocalyptic number.
It is an amenable number.
57200076433 is a deficient number, since it is larger than the sum of its proper divisors (159763823).
57200076433 is a wasteful number, since it uses less digits than its factorization.
57200076433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96695.
The product of its (nonzero) digits is 105840, while the sum is 37.
The spelling of 57200076433 in words is "fifty-seven billion, two hundred million, seventy-six thousand, four hundred thirty-three".
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