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57200234119753 is a prime number
BaseRepresentation
bin11010000000101111101111…
…01000101100001001001001
321111112021210122221102221111
431000113313220230021021
524444132034413313003
6321353231431010321
715022403060550244
oct1500276750541111
9244467718842844
1057200234119753
1117253534a5422a
1264b99568099a1
1325bbc60a0cc6a
14101a712a6625b
15692d9912be6d
hex3405f7a2c249

57200234119753 has 2 divisors, whose sum is σ = 57200234119754. Its totient is φ = 57200234119752.

The previous prime is 57200234119733. The next prime is 57200234119783. The reversal of 57200234119753 is 35791143200275.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 56428160849424 + 772073270329 = 7511868^2 + 878677^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-57200234119753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 57200234119697 and 57200234119706.

It is not a weakly prime, because it can be changed into another prime (57200234119733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28600117059876 + 28600117059877.

It is an arithmetic number, because the mean of its divisors is an integer number (28600117059877).

Almost surely, 257200234119753 is an apocalyptic number.

It is an amenable number.

57200234119753 is a deficient number, since it is larger than the sum of its proper divisors (1).

57200234119753 is an equidigital number, since it uses as much as digits as its factorization.

57200234119753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1587600, while the sum is 49.

The spelling of 57200234119753 in words is "fifty-seven trillion, two hundred billion, two hundred thirty-four million, one hundred nineteen thousand, seven hundred fifty-three".