Base | Representation |
---|---|
bin | 101001101100011110101… |
… | …1000101010101111001011 |
3 | 202021211110112022121202211 |
4 | 1103120331120222233023 |
5 | 1222342044124441142 |
6 | 20104321323005551 |
7 | 1131005351300215 |
oct | 123307530525713 |
9 | 22254415277684 |
10 | 5730516249547 |
11 | 190a331035101 |
12 | 7867423698b7 |
13 | 32750184a6ab |
14 | 15b5038bb5b5 |
15 | 9e0e58ca917 |
hex | 5363d62abcb |
5730516249547 has 2 divisors, whose sum is σ = 5730516249548. Its totient is φ = 5730516249546.
The previous prime is 5730516249473. The next prime is 5730516249677. The reversal of 5730516249547 is 7459426150375.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5730516249547 - 235 = 5696156511179 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5730516249491 and 5730516249500.
It is not a weakly prime, because it can be changed into another prime (5730516241547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2865258124773 + 2865258124774.
It is an arithmetic number, because the mean of its divisors is an integer number (2865258124774).
Almost surely, 25730516249547 is an apocalyptic number.
5730516249547 is a deficient number, since it is larger than the sum of its proper divisors (1).
5730516249547 is an equidigital number, since it uses as much as digits as its factorization.
5730516249547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31752000, while the sum is 58.
The spelling of 5730516249547 in words is "five trillion, seven hundred thirty billion, five hundred sixteen million, two hundred forty-nine thousand, five hundred forty-seven".
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