Base | Representation |
---|---|
bin | 101001101101101010001… |
… | …1111111010001110111001 |
3 | 202022002000012212002001202 |
4 | 1103123110133322032321 |
5 | 1222412242141221031 |
6 | 20105421050223545 |
7 | 1131125234524223 |
oct | 123332437721671 |
9 | 22262005762052 |
10 | 5733051507641 |
11 | 1910412130027 |
12 | 78712b424bb5 |
13 | 327816b73203 |
14 | 15b6a44a9413 |
15 | 9e1e326d2cb |
hex | 536d47fa3b9 |
5733051507641 has 2 divisors, whose sum is σ = 5733051507642. Its totient is φ = 5733051507640.
The previous prime is 5733051507619. The next prime is 5733051507721. The reversal of 5733051507641 is 1467051503375.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4481329117225 + 1251722390416 = 2116915^2 + 1118804^2 .
It is a cyclic number.
It is not a de Polignac number, because 5733051507641 - 218 = 5733051245497 is a prime.
It is not a weakly prime, because it can be changed into another prime (5733051507611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2866525753820 + 2866525753821.
It is an arithmetic number, because the mean of its divisors is an integer number (2866525753821).
Almost surely, 25733051507641 is an apocalyptic number.
It is an amenable number.
5733051507641 is a deficient number, since it is larger than the sum of its proper divisors (1).
5733051507641 is an equidigital number, since it uses as much as digits as its factorization.
5733051507641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1323000, while the sum is 47.
The spelling of 5733051507641 in words is "five trillion, seven hundred thirty-three billion, fifty-one million, five hundred seven thousand, six hundred forty-one".
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