Base | Representation |
---|---|
bin | 101001101111001100101… |
… | …1100100100100011011001 |
3 | 202022101112111100200011201 |
4 | 1103132121130210203121 |
5 | 1222441024032301321 |
6 | 20111125003354201 |
7 | 1131303146212243 |
oct | 123363134444331 |
9 | 22271474320151 |
10 | 5736355743961 |
11 | 19118582a8747 |
12 | 7878b1b22961 |
13 | 327c225a982b |
14 | 15b8d9269093 |
15 | 9e3383ab291 |
hex | 537997248d9 |
5736355743961 has 2 divisors, whose sum is σ = 5736355743962. Its totient is φ = 5736355743960.
The previous prime is 5736355743887. The next prime is 5736355744001. The reversal of 5736355743961 is 1693475536375.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4383830937600 + 1352524806361 = 2093760^2 + 1162981^2 .
It is a cyclic number.
It is not a de Polignac number, because 5736355743961 - 215 = 5736355711193 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5736355743893 and 5736355743902.
It is not a weakly prime, because it can be changed into another prime (5736355743661) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2868177871980 + 2868177871981.
It is an arithmetic number, because the mean of its divisors is an integer number (2868177871981).
Almost surely, 25736355743961 is an apocalyptic number.
It is an amenable number.
5736355743961 is a deficient number, since it is larger than the sum of its proper divisors (1).
5736355743961 is an equidigital number, since it uses as much as digits as its factorization.
5736355743961 is an evil number, because the sum of its binary digits is even.
The product of its digits is 214326000, while the sum is 64.
The spelling of 5736355743961 in words is "five trillion, seven hundred thirty-six billion, three hundred fifty-five million, seven hundred forty-three thousand, nine hundred sixty-one".
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