Base | Representation |
---|---|
bin | 101001110111010001010… |
… | …0111001111001101011011 |
3 | 202101001021111200211221212 |
4 | 1103232202213033031123 |
5 | 1223232023441414001 |
6 | 20123113004053335 |
7 | 1132455533665055 |
oct | 123564247171533 |
9 | 22331244624855 |
10 | 5753689404251 |
11 | 1919142741228 |
12 | 78b12ab3424b |
13 | 329755754a59 |
14 | 15c6a13a08d5 |
15 | 9e9eeee07bb |
hex | 53ba29cf35b |
5753689404251 has 2 divisors, whose sum is σ = 5753689404252. Its totient is φ = 5753689404250.
The previous prime is 5753689404209. The next prime is 5753689404277. The reversal of 5753689404251 is 1524049863575.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5753689404251 - 242 = 1355642893147 is a prime.
It is not a weakly prime, because it can be changed into another prime (5753689407251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2876844702125 + 2876844702126.
It is an arithmetic number, because the mean of its divisors is an integer number (2876844702126).
It is a 1-persistent number, because it is pandigital, but 2⋅5753689404251 = 11507378808502 is not.
Almost surely, 25753689404251 is an apocalyptic number.
5753689404251 is a deficient number, since it is larger than the sum of its proper divisors (1).
5753689404251 is an equidigital number, since it uses as much as digits as its factorization.
5753689404251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36288000, while the sum is 59.
The spelling of 5753689404251 in words is "five trillion, seven hundred fifty-three billion, six hundred eighty-nine million, four hundred four thousand, two hundred fifty-one".
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