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5761433 is a prime number
BaseRepresentation
bin10101111110100110011001
3101211201012102
4111332212121
52433331213
6323253145
766654116
oct25764631
911751172
105761433
113285717
121b1a1b5
131269542
14a9d90d
1578c158
hex57e999

5761433 has 2 divisors, whose sum is σ = 5761434. Its totient is φ = 5761432.

The previous prime is 5761423. The next prime is 5761439. The reversal of 5761433 is 3341675.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4963984 + 797449 = 2228^2 + 893^2 .

It is a cyclic number.

It is not a de Polignac number, because 5761433 - 24 = 5761417 is a prime.

It is a super-2 number, since 2×57614332 = 66388220426978, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5761396 and 5761405.

It is not a weakly prime, because it can be changed into another prime (5761439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2880716 + 2880717.

It is an arithmetic number, because the mean of its divisors is an integer number (2880717).

Almost surely, 25761433 is an apocalyptic number.

It is an amenable number.

5761433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5761433 is an equidigital number, since it uses as much as digits as its factorization.

5761433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7560, while the sum is 29.

The square root of 5761433 is about 2400.2985231008. The cubic root of 5761433 is about 179.2710540302.

The spelling of 5761433 in words is "five million, seven hundred sixty-one thousand, four hundred thirty-three".