Base | Representation |
---|---|
bin | 110110001100111010… |
… | …100101001010010011 |
3 | 12120012222012101211001 |
4 | 312030322211022103 |
5 | 1423142334213101 |
6 | 42423001002431 |
7 | 4130135066431 |
oct | 661472451223 |
9 | 176188171731 |
10 | 58198741651 |
11 | 22755743aa6 |
12 | b342783417 |
13 | 564651944b |
14 | 2b6156dd51 |
15 | 17a954b901 |
hex | d8cea5293 |
58198741651 has 2 divisors, whose sum is σ = 58198741652. Its totient is φ = 58198741650.
The previous prime is 58198741609. The next prime is 58198741723. The reversal of 58198741651 is 15614789185.
58198741651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 58198741651 - 211 = 58198739603 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 58198741592 and 58198741601.
It is not a weakly prime, because it can be changed into another prime (58198741451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29099370825 + 29099370826.
It is an arithmetic number, because the mean of its divisors is an integer number (29099370826).
Almost surely, 258198741651 is an apocalyptic number.
58198741651 is a deficient number, since it is larger than the sum of its proper divisors (1).
58198741651 is an equidigital number, since it uses as much as digits as its factorization.
58198741651 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2419200, while the sum is 55.
The spelling of 58198741651 in words is "fifty-eight billion, one hundred ninety-eight million, seven hundred forty-one thousand, six hundred fifty-one".
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