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58343000034377 is a prime number
BaseRepresentation
bin11010100010000000010011…
…10010101100110001001001
321122120112110222121202202002
431101000021302230301021
530121342431002100002
6324030223150320345
715201066633551522
oct1521001162546111
9248515428552662
1058343000034377
111765414457a913
1266633207b90b5
13267294b8c2356
141059b5dbab849
156b297e31a002
hex351009cacc49

58343000034377 has 2 divisors, whose sum is σ = 58343000034378. Its totient is φ = 58343000034376.

The previous prime is 58343000034343. The next prime is 58343000034413. The reversal of 58343000034377 is 77343000034385.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 55478007102736 + 2864992931641 = 7448356^2 + 1692629^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-58343000034377 is a prime.

It is a super-3 number, since 3×583430000343773 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (58343000034337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29171500017188 + 29171500017189.

It is an arithmetic number, because the mean of its divisors is an integer number (29171500017189).

Almost surely, 258343000034377 is an apocalyptic number.

It is an amenable number.

58343000034377 is a deficient number, since it is larger than the sum of its proper divisors (1).

58343000034377 is an equidigital number, since it uses as much as digits as its factorization.

58343000034377 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 47.

The spelling of 58343000034377 in words is "fifty-eight trillion, three hundred forty-three billion, thirty-four thousand, three hundred seventy-seven".