Search a number
-
+
5837676134401 = 7098233675789
BaseRepresentation
bin101010011110011000010…
…0111001100000000000001
3202200002001200112210121001
41110330300213030000001
51231121030042300101
620225442535132001
71141521025264456
oct124746047140001
922602050483531
105837676134401
111950820a98711
127a3469b14001
1333464b813297
1416278b7d782d
15a1cb84b2901
hex54f309cc001

5837676134401 has 4 divisors (see below), whose sum is σ = 5845909810900. Its totient is φ = 5829442457904.

The previous prime is 5837676134399. The next prime is 5837676134471. The reversal of 5837676134401 is 1044316767385.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 332927846001 + 5504748288400 = 576999^2 + 2346220^2 .

It is a cyclic number.

It is not a de Polignac number, because 5837676134401 - 21 = 5837676134399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5837676134471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4116837186 + ... + 4116838603.

It is an arithmetic number, because the mean of its divisors is an integer number (1461477452725).

Almost surely, 25837676134401 is an apocalyptic number.

It is an amenable number.

5837676134401 is a deficient number, since it is larger than the sum of its proper divisors (8233676499).

5837676134401 is an equidigital number, since it uses as much as digits as its factorization.

5837676134401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8233676498.

The product of its (nonzero) digits is 10160640, while the sum is 55.

The spelling of 5837676134401 in words is "five trillion, eight hundred thirty-seven billion, six hundred seventy-six million, one hundred thirty-four thousand, four hundred one".

Divisors: 1 709 8233675789 5837676134401