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5883347497121 is a prime number
BaseRepresentation
bin101010110011101001011…
…0101100111000010100001
3202211102221121021102011122
41111213102311213002201
51232343043424401441
620302434511022025
71145025556412453
oct125472265470241
922742847242148
105883347497121
111969128313486
127b029520a915
13338a49847b73
14164a812a82d3
15a308cd1834b
hex559d2d670a1

5883347497121 has 2 divisors, whose sum is σ = 5883347497122. Its totient is φ = 5883347497120.

The previous prime is 5883347497103. The next prime is 5883347497127. The reversal of 5883347497121 is 1217947433885.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5746994549521 + 136352947600 = 2397289^2 + 369260^2 .

It is a cyclic number.

It is not a de Polignac number, because 5883347497121 - 26 = 5883347497057 is a prime.

It is a super-2 number, since 2×58833474971212 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5883347497127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2941673748560 + 2941673748561.

It is an arithmetic number, because the mean of its divisors is an integer number (2941673748561).

Almost surely, 25883347497121 is an apocalyptic number.

It is an amenable number.

5883347497121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5883347497121 is an equidigital number, since it uses as much as digits as its factorization.

5883347497121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 40642560, while the sum is 62.

The spelling of 5883347497121 in words is "five trillion, eight hundred eighty-three billion, three hundred forty-seven million, four hundred ninety-seven thousand, one hundred twenty-one".