Search a number
-
+
5884058124401 is a prime number
BaseRepresentation
bin101010110011111110100…
…1100011100000001110001
3202211111210010110000112112
41111213331030130001301
51232401022334440101
620303033214135105
71145052305555222
oct125477514340161
922744703400475
105884058124401
111969462461256
127b04531b1495
13338b30b38492
14164b0b80b249
15a30d03d96bb
hex559fd31c071

5884058124401 has 2 divisors, whose sum is σ = 5884058124402. Its totient is φ = 5884058124400.

The previous prime is 5884058124391. The next prime is 5884058124437. The reversal of 5884058124401 is 1044218504885.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5606244798001 + 277813326400 = 2367751^2 + 527080^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5884058124401 is a prime.

It is a super-2 number, since 2×58840581244012 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 5884058124401.

It is not a weakly prime, because it can be changed into another prime (5884058144401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2942029062200 + 2942029062201.

It is an arithmetic number, because the mean of its divisors is an integer number (2942029062201).

Almost surely, 25884058124401 is an apocalyptic number.

It is an amenable number.

5884058124401 is a deficient number, since it is larger than the sum of its proper divisors (1).

5884058124401 is an equidigital number, since it uses as much as digits as its factorization.

5884058124401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1638400, while the sum is 50.

The spelling of 5884058124401 in words is "five trillion, eight hundred eighty-four billion, fifty-eight million, one hundred twenty-four thousand, four hundred one".