Base | Representation |
---|---|
bin | 110111000011111101… |
… | …010101000001001011 |
3 | 12122121022212101122122 |
4 | 313003331111001023 |
5 | 1432040241140333 |
6 | 43054350041455 |
7 | 4162050324545 |
oct | 670375250113 |
9 | 178538771578 |
10 | 59122208843 |
11 | 23089a44625 |
12 | b55baa928b |
13 | 576293b439 |
14 | 2c0c078695 |
15 | 1810661798 |
hex | dc3f5504b |
59122208843 has 2 divisors, whose sum is σ = 59122208844. Its totient is φ = 59122208842.
The previous prime is 59122208807. The next prime is 59122208851. The reversal of 59122208843 is 34880222195.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 59122208843 - 228 = 58853773387 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 59122208794 and 59122208803.
It is not a weakly prime, because it can be changed into another prime (59122208143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29561104421 + 29561104422.
It is an arithmetic number, because the mean of its divisors is an integer number (29561104422).
Almost surely, 259122208843 is an apocalyptic number.
59122208843 is a deficient number, since it is larger than the sum of its proper divisors (1).
59122208843 is an equidigital number, since it uses as much as digits as its factorization.
59122208843 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 276480, while the sum is 44.
The spelling of 59122208843 in words is "fifty-nine billion, one hundred twenty-two million, two hundred eight thousand, eight hundred forty-three".
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