Base | Representation |
---|---|
bin | 1011000001010111… |
… | …01010100011000001 |
3 | 120021100221002102112 |
4 | 11200223222203001 |
5 | 44104224321442 |
6 | 2415050225105 |
7 | 266425616054 |
oct | 54053524301 |
9 | 16240832375 |
10 | 5917026497 |
11 | 2567009648 |
12 | 1191725195 |
13 | 733b37115 |
14 | 401bb0a9b |
15 | 2496e8082 |
hex | 160aea8c1 |
5917026497 has 2 divisors, whose sum is σ = 5917026498. Its totient is φ = 5917026496.
The previous prime is 5917026469. The next prime is 5917026527. The reversal of 5917026497 is 7946207195.
5917026497 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3715633936 + 2201392561 = 60956^2 + 46919^2 .
It is a cyclic number.
It is not a de Polignac number, because 5917026497 - 228 = 5648591041 is a prime.
It is a super-2 number, since 2×59170264972 = 70022405132400182018, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5917026407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2958513248 + 2958513249.
It is an arithmetic number, because the mean of its divisors is an integer number (2958513249).
Almost surely, 25917026497 is an apocalyptic number.
It is an amenable number.
5917026497 is a deficient number, since it is larger than the sum of its proper divisors (1).
5917026497 is an equidigital number, since it uses as much as digits as its factorization.
5917026497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 952560, while the sum is 50.
The square root of 5917026497 is about 76922.2106871611. The cubic root of 5917026497 is about 1808.7054117919.
The spelling of 5917026497 in words is "five billion, nine hundred seventeen million, twenty-six thousand, four hundred ninety-seven".
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