Base | Representation |
---|---|
bin | 1011000010011110… |
… | …01100001001001011 |
3 | 120022000110012222111 |
4 | 11201033030021023 |
5 | 44114120323042 |
6 | 2420022003151 |
7 | 266601023461 |
oct | 54117141113 |
9 | 16260405874 |
10 | 5926339147 |
11 | 257129a353 |
12 | 11948764b7 |
13 | 735a47b71 |
14 | 403116831 |
15 | 24a437517 |
hex | 1613cc24b |
5926339147 has 4 divisors (see below), whose sum is σ = 5926559320. Its totient is φ = 5926118976.
The previous prime is 5926339123. The next prime is 5926339151. The reversal of 5926339147 is 7419336295.
5926339147 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5926339147 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5926339147.
It is not an unprimeable number, because it can be changed into a prime (5926339157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62997 + ... + 125782.
It is an arithmetic number, because the mean of its divisors is an integer number (1481639830).
Almost surely, 25926339147 is an apocalyptic number.
5926339147 is a deficient number, since it is larger than the sum of its proper divisors (220173).
5926339147 is a wasteful number, since it uses less digits than its factorization.
5926339147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 220172.
The product of its digits is 1224720, while the sum is 49.
The square root of 5926339147 is about 76982.7197947695. The cubic root of 5926339147 is about 1809.6538054651.
The spelling of 5926339147 in words is "five billion, nine hundred twenty-six million, three hundred thirty-nine thousand, one hundred forty-seven".
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