Base | Representation |
---|---|
bin | 101011001110011101111… |
… | …0110101010011110011011 |
3 | 210000221121121011200011102 |
4 | 1112130323312222132123 |
5 | 1234314023123041432 |
6 | 20345122035022015 |
7 | 1152135062264324 |
oct | 126347366523633 |
9 | 23027547150142 |
10 | 5940943955867 |
11 | 19905a3a8a408 |
12 | 7bb48a13a90b |
13 | 3412c834959b |
14 | 16778685944b |
15 | a480e545962 |
hex | 5673bdaa79b |
5940943955867 has 2 divisors, whose sum is σ = 5940943955868. Its totient is φ = 5940943955866.
The previous prime is 5940943955777. The next prime is 5940943955897. The reversal of 5940943955867 is 7685593490495.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5940943955867 - 230 = 5939870214043 is a prime.
It is a super-3 number, since 3×59409439558673 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5940943955794 and 5940943955803.
It is not a weakly prime, because it can be changed into another prime (5940943955897) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2970471977933 + 2970471977934.
It is an arithmetic number, because the mean of its divisors is an integer number (2970471977934).
Almost surely, 25940943955867 is an apocalyptic number.
5940943955867 is a deficient number, since it is larger than the sum of its proper divisors (1).
5940943955867 is an equidigital number, since it uses as much as digits as its factorization.
5940943955867 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1469664000, while the sum is 74.
The spelling of 5940943955867 in words is "five trillion, nine hundred forty billion, nine hundred forty-three million, nine hundred fifty-five thousand, eight hundred sixty-seven".
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