Base | Representation |
---|---|
bin | 110111010101001110… |
… | …010101100001110001 |
3 | 12200100111221012211211 |
4 | 313111032111201301 |
5 | 1433133420130144 |
6 | 43143214440121 |
7 | 4202165435164 |
oct | 672516254161 |
9 | 180314835754 |
10 | 59411880049 |
11 | 23218503915 |
12 | b620b03041 |
13 | 57aa960b12 |
14 | 2c3871dadb |
15 | 182acd0034 |
hex | dd5395871 |
59411880049 has 2 divisors, whose sum is σ = 59411880050. Its totient is φ = 59411880048.
The previous prime is 59411879987. The next prime is 59411880061. The reversal of 59411880049 is 94008811495.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59253296400 + 158583649 = 243420^2 + 12593^2 .
It is a cyclic number.
It is not a de Polignac number, because 59411880049 - 231 = 57264396401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 59411879984 and 59411880011.
It is not a weakly prime, because it can be changed into another prime (59411880079) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29705940024 + 29705940025.
It is an arithmetic number, because the mean of its divisors is an integer number (29705940025).
Almost surely, 259411880049 is an apocalyptic number.
It is an amenable number.
59411880049 is a deficient number, since it is larger than the sum of its proper divisors (1).
59411880049 is an equidigital number, since it uses as much as digits as its factorization.
59411880049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 414720, while the sum is 49.
The spelling of 59411880049 in words is "fifty-nine billion, four hundred eleven million, eight hundred eighty thousand, forty-nine".
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