Base | Representation |
---|---|
bin | 101011001110100110110… |
… | …1001001101010010110001 |
3 | 210000222101101210010201120 |
4 | 1112131031221031102301 |
5 | 1234320131024341403 |
6 | 20345211420052453 |
7 | 1152145345211334 |
oct | 126351551152261 |
9 | 23028341703646 |
10 | 5941242418353 |
11 | 1990737503720 |
12 | 7bb552094129 |
13 | 3413451295c8 |
14 | 1677b434c61b |
15 | a482a84de53 |
hex | 5674da4d4b1 |
5941242418353 has 32 divisors (see below), whose sum is σ = 9096829493760. Its totient is φ = 3411168272640.
The previous prime is 5941242418297. The next prime is 5941242418369. The reversal of 5941242418353 is 3538142421495.
It is not a de Polignac number, because 5941242418353 - 29 = 5941242417841 is a prime.
It is a super-2 number, since 2×59412424183532 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5941242418296 and 5941242418305.
It is not an unprimeable number, because it can be changed into a prime (5941242418373) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 50272150 + ... + 50390192.
It is an arithmetic number, because the mean of its divisors is an integer number (284275921680).
Almost surely, 25941242418353 is an apocalyptic number.
It is an amenable number.
5941242418353 is a deficient number, since it is larger than the sum of its proper divisors (3155587075407).
5941242418353 is a wasteful number, since it uses less digits than its factorization.
5941242418353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 198349.
The product of its digits is 4147200, while the sum is 51.
The spelling of 5941242418353 in words is "five trillion, nine hundred forty-one billion, two hundred forty-two million, four hundred eighteen thousand, three hundred fifty-three".
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