Base | Representation |
---|---|
bin | 101011010111100010001… |
… | …0101101110111011111001 |
3 | 210002210212110212200112212 |
4 | 1112233010111232323321 |
5 | 1240123411344434121 |
6 | 20402102022344505 |
7 | 1153424415161555 |
oct | 126570425567371 |
9 | 23083773780485 |
10 | 5960413671161 |
11 | 1998885147704 |
12 | 80320258b135 |
13 | 3430abbc7691 |
14 | 1686b2544865 |
15 | a509d96525b |
hex | 56bc456eef9 |
5960413671161 has 2 divisors, whose sum is σ = 5960413671162. Its totient is φ = 5960413671160.
The previous prime is 5960413671137. The next prime is 5960413671169. The reversal of 5960413671161 is 1611763140695.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4643783643136 + 1316630028025 = 2154944^2 + 1147445^2 .
It is a cyclic number.
It is not a de Polignac number, because 5960413671161 - 210 = 5960413670137 is a prime.
It is a super-2 number, since 2×59604136711612 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5960413671169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2980206835580 + 2980206835581.
It is an arithmetic number, because the mean of its divisors is an integer number (2980206835581).
Almost surely, 25960413671161 is an apocalyptic number.
It is an amenable number.
5960413671161 is a deficient number, since it is larger than the sum of its proper divisors (1).
5960413671161 is an equidigital number, since it uses as much as digits as its factorization.
5960413671161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 816480, while the sum is 50.
The spelling of 5960413671161 in words is "five trillion, nine hundred sixty billion, four hundred thirteen million, six hundred seventy-one thousand, one hundred sixty-one".
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