Base | Representation |
---|---|
bin | 11011001111110110010111… |
… | …10010110111111000000001 |
3 | 21212011010101021111212002012 |
4 | 31213323023302313320001 |
5 | 30323144444444440423 |
6 | 331234014052502305 |
7 | 15422643113114054 |
oct | 1547731362677001 |
9 | 255133337455065 |
10 | 59918212890113 |
11 | 18101198125a06 |
12 | 687867431a995 |
13 | 275835641a806 |
14 | 10b20b24bca9b |
15 | 6dd924775078 |
hex | 367ecbcb7e01 |
59918212890113 has 2 divisors, whose sum is σ = 59918212890114. Its totient is φ = 59918212890112.
The previous prime is 59918212890089. The next prime is 59918212890127. The reversal of 59918212890113 is 31109821281995.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30826558395889 + 29091654494224 = 5552167^2 + 5393668^2 .
It is a cyclic number.
It is not a de Polignac number, because 59918212890113 - 210 = 59918212889089 is a prime.
It is not a weakly prime, because it can be changed into another prime (59918212890013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29959106445056 + 29959106445057.
It is an arithmetic number, because the mean of its divisors is an integer number (29959106445057).
Almost surely, 259918212890113 is an apocalyptic number.
It is an amenable number.
59918212890113 is a deficient number, since it is larger than the sum of its proper divisors (1).
59918212890113 is an equidigital number, since it uses as much as digits as its factorization.
59918212890113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2799360, while the sum is 59.
The spelling of 59918212890113 in words is "fifty-nine trillion, nine hundred eighteen billion, two hundred twelve million, eight hundred ninety thousand, one hundred thirteen".
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