Base | Representation |
---|---|
bin | 101011100111001001100… |
… | …0101010000110110010011 |
3 | 210020000102110202201102021 |
4 | 1113032103011100312103 |
5 | 1241201100413232103 |
6 | 20425325314232311 |
7 | 1156022410635304 |
oct | 127162305206623 |
9 | 23200373681367 |
10 | 5993947008403 |
11 | 1a01022908262 |
12 | 809800885697 |
13 | 3462c42cc073 |
14 | 16a173d487ab |
15 | a5db2883bbd |
hex | 57393150d93 |
5993947008403 has 2 divisors, whose sum is σ = 5993947008404. Its totient is φ = 5993947008402.
The previous prime is 5993947008377. The next prime is 5993947008449. The reversal of 5993947008403 is 3048007493995.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5993947008403 is a prime.
It is a super-2 number, since 2×59939470084032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5993947008473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2996973504201 + 2996973504202.
It is an arithmetic number, because the mean of its divisors is an integer number (2996973504202).
Almost surely, 25993947008403 is an apocalyptic number.
5993947008403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5993947008403 is an equidigital number, since it uses as much as digits as its factorization.
5993947008403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 29393280, while the sum is 61.
The spelling of 5993947008403 in words is "five trillion, nine hundred ninety-three billion, nine hundred forty-seven million, eight thousand, four hundred three".
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