Base | Representation |
---|---|
bin | 11011010010001010000010… |
… | …00101100011001110000001 |
3 | 21212102201000020122000010021 |
4 | 31221011001011203032001 |
5 | 30330444324433204331 |
6 | 331334244431133441 |
7 | 15431450510416513 |
oct | 1551050105431601 |
9 | 255381006560107 |
10 | 59997490131841 |
11 | 1813187a058aa9 |
12 | 688baba074281 |
13 | 276297b8a54c2 |
14 | 10b5c73277bb3 |
15 | 6e0a14578211 |
hex | 369141163381 |
59997490131841 has 2 divisors, whose sum is σ = 59997490131842. Its totient is φ = 59997490131840.
The previous prime is 59997490131643. The next prime is 59997490131853. The reversal of 59997490131841 is 14813109479995.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44017651776400 + 15979838355441 = 6634580^2 + 3997479^2 .
It is a cyclic number.
It is not a de Polignac number, because 59997490131841 - 219 = 59997489607553 is a prime.
It is not a weakly prime, because it can be changed into another prime (59997490131871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29998745065920 + 29998745065921.
It is an arithmetic number, because the mean of its divisors is an integer number (29998745065921).
Almost surely, 259997490131841 is an apocalyptic number.
It is an amenable number.
59997490131841 is a deficient number, since it is larger than the sum of its proper divisors (1).
59997490131841 is an equidigital number, since it uses as much as digits as its factorization.
59997490131841 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 88179840, while the sum is 70.
The spelling of 59997490131841 in words is "fifty-nine trillion, nine hundred ninety-seven billion, four hundred ninety million, one hundred thirty-one thousand, eight hundred forty-one".
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