Search a number
-
+
60115468313 is a prime number
BaseRepresentation
bin110111111111001010…
…010100000000011001
312202011112212012111102
4313333022110000121
51441104024441223
643341111041145
74225501023005
oct677712240031
9182145765442
1060115468313
112354968411a
12b7986701b5
135890658534
142ca3d4d705
15186c960928
hexdff294019

60115468313 has 2 divisors, whose sum is σ = 60115468314. Its totient is φ = 60115468312.

The previous prime is 60115468271. The next prime is 60115468339. The reversal of 60115468313 is 31386451106.

60115468313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53510330329 + 6605137984 = 231323^2 + 81272^2 .

It is a cyclic number.

It is not a de Polignac number, because 60115468313 - 212 = 60115464217 is a prime.

It is a super-2 number, since 2×601154683132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (60115461313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30057734156 + 30057734157.

It is an arithmetic number, because the mean of its divisors is an integer number (30057734157).

Almost surely, 260115468313 is an apocalyptic number.

It is an amenable number.

60115468313 is a deficient number, since it is larger than the sum of its proper divisors (1).

60115468313 is an equidigital number, since it uses as much as digits as its factorization.

60115468313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 38.

The spelling of 60115468313 in words is "sixty billion, one hundred fifteen million, four hundred sixty-eight thousand, three hundred thirteen".