Base | Representation |
---|---|
bin | 1011001100101011… |
… | …11100110011011011 |
3 | 120111222122010000111 |
4 | 11212111330303123 |
5 | 44303032404103 |
6 | 2432321545151 |
7 | 301661064136 |
oct | 54625746333 |
9 | 16458563014 |
10 | 6011997403 |
11 | 26056856a5 |
12 | 11b94a51b7 |
13 | 74a709819 |
14 | 41065321d |
15 | 252c0786d |
hex | 16657ccdb |
6011997403 has 4 divisors (see below), whose sum is σ = 6158631528. Its totient is φ = 5865363280.
The previous prime is 6011997401. The next prime is 6011997413. The reversal of 6011997403 is 3047991106.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 6011997403 - 21 = 6011997401 is a prime.
It is a super-2 number, since 2×60119974032 = 72288225547357488818, which contains 22 as substring.
It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6011997401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73317001 + ... + 73317082.
It is an arithmetic number, because the mean of its divisors is an integer number (1539657882).
Almost surely, 26011997403 is an apocalyptic number.
6011997403 is a deficient number, since it is larger than the sum of its proper divisors (146634125).
6011997403 is a wasteful number, since it uses less digits than its factorization.
6011997403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 146634124.
The product of its (nonzero) digits is 40824, while the sum is 40.
The square root of 6011997403 is about 77537.0711530942. The cubic root of 6011997403 is about 1818.3309380265.
The spelling of 6011997403 in words is "six billion, eleven million, nine hundred ninety-seven thousand, four hundred three".
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