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601314113 is a prime number
BaseRepresentation
bin100011110101110…
…101001101000001
31112220110220220002
4203311311031001
52212414022423
6135400125345
720621041241
oct4365651501
91486426802
10601314113
11289476214
12149466855
1397768a8a
1459c09b21
1537bcc228
hex23d75341

601314113 has 2 divisors, whose sum is σ = 601314114. Its totient is φ = 601314112.

The previous prime is 601314073. The next prime is 601314137. The reversal of 601314113 is 311413106.

601314113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 576384064 + 24930049 = 24008^2 + 4993^2 .

It is a cyclic number.

It is not a de Polignac number, because 601314113 - 28 = 601313857 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (601314143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300657056 + 300657057.

It is an arithmetic number, because the mean of its divisors is an integer number (300657057).

Almost surely, 2601314113 is an apocalyptic number.

It is an amenable number.

601314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

601314113 is an equidigital number, since it uses as much as digits as its factorization.

601314113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

The square root of 601314113 is about 24521.7069756573. The cubic root of 601314113 is about 844.0479750999.

Adding to 601314113 its reverse (311413106), we get a palindrome (912727219).

The spelling of 601314113 in words is "six hundred one million, three hundred fourteen thousand, one hundred thirteen".