Base | Representation |
---|---|
bin | 11011100000100111000010… |
… | …01110110011000100010001 |
3 | 21221012011211201020011112201 |
4 | 31300103201032303010101 |
5 | 30412113403111242044 |
6 | 332354334404323201 |
7 | 15512361101054233 |
oct | 1560234116630421 |
9 | 257164751204481 |
10 | 60494098149649 |
11 | 1830344836702a |
12 | 69501b30a3501 |
13 | 279a752076a08 |
14 | 10d1d03bba253 |
15 | 6ed8cc4d97d4 |
hex | 3704e13b3111 |
60494098149649 has 2 divisors, whose sum is σ = 60494098149650. Its totient is φ = 60494098149648.
The previous prime is 60494098149619. The next prime is 60494098149697. The reversal of 60494098149649 is 94694189049406.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52052516556049 + 8441581593600 = 7214743^2 + 2905440^2 .
It is a cyclic number.
It is not a de Polignac number, because 60494098149649 - 211 = 60494098147601 is a prime.
It is not a weakly prime, because it can be changed into another prime (60494098149619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30247049074824 + 30247049074825.
It is an arithmetic number, because the mean of its divisors is an integer number (30247049074825).
Almost surely, 260494098149649 is an apocalyptic number.
It is an amenable number.
60494098149649 is a deficient number, since it is larger than the sum of its proper divisors (1).
60494098149649 is an equidigital number, since it uses as much as digits as its factorization.
60494098149649 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483729408, while the sum is 73.
The spelling of 60494098149649 in words is "sixty trillion, four hundred ninety-four billion, ninety-eight million, one hundred forty-nine thousand, six hundred forty-nine".
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