Base | Representation |
---|---|
bin | 111000110101110110… |
… | …100000111100101011 |
3 | 12211112111101221002101 |
4 | 320311312200330223 |
5 | 1444443423302243 |
6 | 44012125314231 |
7 | 4260312104224 |
oct | 706566407453 |
9 | 184474357071 |
10 | 61033025323 |
11 | 2397a6082a6 |
12 | b9b3a05977 |
13 | 59a878b38a |
14 | 2d4db5a24b |
15 | 18c32a954d |
hex | e35da0f2b |
61033025323 has 4 divisors (see below), whose sum is σ = 61056565528. Its totient is φ = 61009485120.
The previous prime is 61033025311. The next prime is 61033025353. The reversal of 61033025323 is 32352033016.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-61033025323 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 61033025291 and 61033025300.
It is not an unprimeable number, because it can be changed into a prime (61033025353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11766213 + ... + 11771398.
It is an arithmetic number, because the mean of its divisors is an integer number (15264141382).
Almost surely, 261033025323 is an apocalyptic number.
61033025323 is a deficient number, since it is larger than the sum of its proper divisors (23540205).
61033025323 is a wasteful number, since it uses less digits than its factorization.
61033025323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23540204.
The product of its (nonzero) digits is 9720, while the sum is 28.
Adding to 61033025323 its reverse (32352033016), we get a palindrome (93385058339).
The spelling of 61033025323 in words is "sixty-one billion, thirty-three million, twenty-five thousand, three hundred twenty-three".
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