Base | Representation |
---|---|
bin | 111000111010011100… |
… | …100010000010010001 |
3 | 12211201212102201211020 |
4 | 320322130202002101 |
5 | 2000123141200423 |
6 | 44023521310053 |
7 | 4262236165116 |
oct | 707234420221 |
9 | 184655381736 |
10 | 61110100113 |
11 | 23a0a070777 |
12 | ba15795329 |
13 | 59bb73616a |
14 | 2d5a0a090d |
15 | 18c9e314e3 |
hex | e3a722091 |
61110100113 has 8 divisors (see below), whose sum is σ = 81481598976. Its totient is φ = 40739334000.
The previous prime is 61110100111. The next prime is 61110100147. The reversal of 61110100113 is 31100101116.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 61110100113 - 21 = 61110100111 is a prime.
It is a super-2 number, since 2×611101001132 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 61110100092 and 61110100101.
It is not an unprimeable number, because it can be changed into a prime (61110100111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56043 + ... + 354063.
It is an arithmetic number, because the mean of its divisors is an integer number (10185199872).
Almost surely, 261110100113 is an apocalyptic number.
It is an amenable number.
61110100113 is a deficient number, since it is larger than the sum of its proper divisors (20371498863).
61110100113 is a wasteful number, since it uses less digits than its factorization.
61110100113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 366375.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 61110100113 its reverse (31100101116), we get a palindrome (92210201229).
The spelling of 61110100113 in words is "sixty-one billion, one hundred ten million, one hundred thousand, one hundred thirteen".
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