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61110100113 = 368351298021
BaseRepresentation
bin111000111010011100…
…100010000010010001
312211201212102201211020
4320322130202002101
52000123141200423
644023521310053
74262236165116
oct707234420221
9184655381736
1061110100113
1123a0a070777
12ba15795329
1359bb73616a
142d5a0a090d
1518c9e314e3
hexe3a722091

61110100113 has 8 divisors (see below), whose sum is σ = 81481598976. Its totient is φ = 40739334000.

The previous prime is 61110100111. The next prime is 61110100147. The reversal of 61110100113 is 31100101116.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 61110100113 - 21 = 61110100111 is a prime.

It is a super-2 number, since 2×611101001132 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 61110100092 and 61110100101.

It is not an unprimeable number, because it can be changed into a prime (61110100111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56043 + ... + 354063.

It is an arithmetic number, because the mean of its divisors is an integer number (10185199872).

Almost surely, 261110100113 is an apocalyptic number.

It is an amenable number.

61110100113 is a deficient number, since it is larger than the sum of its proper divisors (20371498863).

61110100113 is a wasteful number, since it uses less digits than its factorization.

61110100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 366375.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 61110100113 its reverse (31100101116), we get a palindrome (92210201229).

The spelling of 61110100113 in words is "sixty-one billion, one hundred ten million, one hundred thousand, one hundred thirteen".

Divisors: 1 3 68351 205053 298021 894063 20370033371 61110100113