Base | Representation |
---|---|
bin | 101100011110101001000… |
… | …0001110001110110110001 |
3 | 210122102000110201122221012 |
4 | 1120331102001301312301 |
5 | 1300124124323112043 |
6 | 21000154234440305 |
7 | 1200441452155625 |
oct | 130752201616661 |
9 | 23572013648835 |
10 | 6113114660273 |
11 | 1a47614947965 |
12 | 828919893095 |
13 | 354605c1883a |
14 | 171c3a905185 |
15 | a9039722a18 |
hex | 58f52071db1 |
6113114660273 has 2 divisors, whose sum is σ = 6113114660274. Its totient is φ = 6113114660272.
The previous prime is 6113114660269. The next prime is 6113114660299. The reversal of 6113114660273 is 3720664113116.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4278845320369 + 1834269339904 = 2068537^2 + 1354352^2 .
It is a cyclic number.
It is not a de Polignac number, because 6113114660273 - 22 = 6113114660269 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6113114660273.
It is not a weakly prime, because it can be changed into another prime (6113114660203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3056557330136 + 3056557330137.
It is an arithmetic number, because the mean of its divisors is an integer number (3056557330137).
Almost surely, 26113114660273 is an apocalyptic number.
It is an amenable number.
6113114660273 is a deficient number, since it is larger than the sum of its proper divisors (1).
6113114660273 is an equidigital number, since it uses as much as digits as its factorization.
6113114660273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108864, while the sum is 41.
Adding to 6113114660273 its reverse (3720664113116), we get a palindrome (9833778773389).
The spelling of 6113114660273 in words is "six trillion, one hundred thirteen billion, one hundred fourteen million, six hundred sixty thousand, two hundred seventy-three".
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