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6113165467153 = 43142166638771
BaseRepresentation
bin101100011110101010100…
…0011100101111000010001
3210122102011000022220212111
41120331111003211320101
51300124230324422103
621000203251425321
71200442640053633
oct130752503457021
923572130286774
106113165467153
111a47640599918
128289328b5241
133546135c7294
14171c4356ca53
15a903de0b86d
hex58f550e5e11

6113165467153 has 4 divisors (see below), whose sum is σ = 6255332105968. Its totient is φ = 5970998828340.

The previous prime is 6113165467141. The next prime is 6113165467181. The reversal of 6113165467153 is 3517645613116.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 6113165467153 - 29 = 6113165466641 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 6113165467097 and 6113165467106.

It is not an unprimeable number, because it can be changed into a prime (6113165467853) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71083319343 + ... + 71083319428.

It is an arithmetic number, because the mean of its divisors is an integer number (1563833026492).

Almost surely, 26113165467153 is an apocalyptic number.

It is an amenable number.

6113165467153 is a deficient number, since it is larger than the sum of its proper divisors (142166638815).

6113165467153 is a wasteful number, since it uses less digits than its factorization.

6113165467153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 142166638814.

The product of its digits is 1360800, while the sum is 49.

The spelling of 6113165467153 in words is "six trillion, one hundred thirteen billion, one hundred sixty-five million, four hundred sixty-seven thousand, one hundred fifty-three".

Divisors: 1 43 142166638771 6113165467153