Base | Representation |
---|---|
bin | 10001110010110101110… |
… | …00011110111001110001 |
3 | 2011110011012222210210011 |
4 | 20321122320132321301 |
5 | 40004131442041423 |
6 | 1144513344334521 |
7 | 62113212130003 |
oct | 10713270367161 |
9 | 2143135883704 |
10 | 611410112113 |
11 | 216330083719 |
12 | 9a5b4014441 |
13 | 4586a827038 |
14 | 218417cc373 |
15 | 10d8691bb0d |
hex | 8e5ae1ee71 |
611410112113 has 2 divisors, whose sum is σ = 611410112114. Its totient is φ = 611410112112.
The previous prime is 611410112023. The next prime is 611410112171. The reversal of 611410112113 is 311211014116.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 611409833329 + 278784 = 781927^2 + 528^2 .
It is a cyclic number.
It is not a de Polignac number, because 611410112113 - 29 = 611410111601 is a prime.
It is not a weakly prime, because it can be changed into another prime (611410112413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 305705056056 + 305705056057.
It is an arithmetic number, because the mean of its divisors is an integer number (305705056057).
Almost surely, 2611410112113 is an apocalyptic number.
It is an amenable number.
611410112113 is a deficient number, since it is larger than the sum of its proper divisors (1).
611410112113 is an equidigital number, since it uses as much as digits as its factorization.
611410112113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 611410112113 its reverse (311211014116), we get a palindrome (922621126229).
The spelling of 611410112113 in words is "six hundred eleven billion, four hundred ten million, one hundred twelve thousand, one hundred thirteen".
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