Base | Representation |
---|---|
bin | 10001110011000001111… |
… | …01101001100111111010 |
3 | 2011110102022221212001222 |
4 | 20321200331221213322 |
5 | 40004334101130132 |
6 | 1144531431112042 |
7 | 62115561225242 |
oct | 10714075514772 |
9 | 2143368855058 |
10 | 611512130042 |
11 | 216382723260 |
12 | 9a622212622 |
13 | 458859c6188 |
14 | 21851186b22 |
15 | 10d9086e412 |
hex | 8e60f699fa |
611512130042 has 32 divisors (see below), whose sum is σ = 1042175735424. Its totient is φ = 266638478400.
The previous prime is 611512129997. The next prime is 611512130051. The reversal of 611512130042 is 240031215116.
It is a super-3 number, since 3×6115121300423 (a number of 36 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 611512129993 and 611512130020.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5232653 + ... + 5348240.
It is an arithmetic number, because the mean of its divisors is an integer number (32567991732).
Almost surely, 2611512130042 is an apocalyptic number.
611512130042 is a deficient number, since it is larger than the sum of its proper divisors (430663605382).
611512130042 is a wasteful number, since it uses less digits than its factorization.
611512130042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10581014.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 611512130042 its reverse (240031215116), we get a palindrome (851543345158).
The spelling of 611512130042 in words is "six hundred eleven billion, five hundred twelve million, one hundred thirty thousand, forty-two".
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