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61201401 = 320400467
BaseRepresentation
bin1110100101110…
…1101111111001
311021011100112120
43221131233321
5111131421101
610023431453
71342126512
oct351355771
9137140476
1061201401
1131601578
12185b5589
13c8aaa61
1481b1a09
15558db36
hex3a5dbf9

61201401 has 4 divisors (see below), whose sum is σ = 81601872. Its totient is φ = 40800932.

The previous prime is 61201391. The next prime is 61201403. The reversal of 61201401 is 10410216.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 61201401 - 25 = 61201369 is a prime.

It is a super-2 number, since 2×612014012 = 7491222968725602, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (61201403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10200231 + ... + 10200236.

It is an arithmetic number, because the mean of its divisors is an integer number (20400468).

Almost surely, 261201401 is an apocalyptic number.

It is an amenable number.

61201401 is a deficient number, since it is larger than the sum of its proper divisors (20400471).

61201401 is a wasteful number, since it uses less digits than its factorization.

61201401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20400470.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 61201401 is about 7823.1324288932. The cubic root of 61201401 is about 394.0824743390.

Adding to 61201401 its reverse (10410216), we get a palindrome (71611617).

The spelling of 61201401 in words is "sixty-one million, two hundred one thousand, four hundred one".

Divisors: 1 3 20400467 61201401