Base | Representation |
---|---|
bin | 11011110110000010100111… |
… | …11000001100010111101001 |
3 | 22000210120112002212100010022 |
4 | 31323001103320030113221 |
5 | 31011144441004331213 |
6 | 334120515132130225 |
7 | 15616516622111120 |
oct | 1573012370142751 |
9 | 260716462770108 |
10 | 61230461011433 |
11 | 18567768a69a0a |
12 | 6a4aa59606975 |
13 | 2822013bb1ccc |
14 | 11197da5d2ab7 |
15 | 712b28acd308 |
hex | 37b053e0c5e9 |
61230461011433 has 16 divisors (see below), whose sum is σ = 74593118976000. Its totient is φ = 49091596409232.
The previous prime is 61230461011427. The next prime is 61230461011453. The reversal of 61230461011433 is 33411016403216.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 61230461011433 - 210 = 61230461010409 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 61230461011393 and 61230461011402.
It is not an unprimeable number, because it can be changed into a prime (61230461011453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2913783203 + ... + 2913804216.
It is an arithmetic number, because the mean of its divisors is an integer number (4662069936000).
Almost surely, 261230461011433 is an apocalyptic number.
It is an amenable number.
61230461011433 is a deficient number, since it is larger than the sum of its proper divisors (13362657964567).
61230461011433 is a wasteful number, since it uses less digits than its factorization.
61230461011433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5827587524.
The product of its (nonzero) digits is 31104, while the sum is 35.
Adding to 61230461011433 its reverse (33411016403216), we get a palindrome (94641477414649).
The spelling of 61230461011433 in words is "sixty-one trillion, two hundred thirty billion, four hundred sixty-one million, eleven thousand, four hundred thirty-three".
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