Base | Representation |
---|---|
bin | 101100100110100000101… |
… | …0110100011110010000001 |
3 | 210201000122021020220010211 |
4 | 1121031001112203302001 |
5 | 1300413232234423121 |
6 | 21012031230354121 |
7 | 1201610323526551 |
oct | 131150126436201 |
9 | 23630567226124 |
10 | 6130014764161 |
11 | 1a537a7586072 |
12 | 83005565b941 |
13 | 35609a303802 |
14 | 1729a121d161 |
15 | a96c8265ce1 |
hex | 593415a3c81 |
6130014764161 has 2 divisors, whose sum is σ = 6130014764162. Its totient is φ = 6130014764160.
The previous prime is 6130014764129. The next prime is 6130014764179. The reversal of 6130014764161 is 1614674100316.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4374138005136 + 1755876759025 = 2091444^2 + 1325095^2 .
It is a cyclic number.
It is not a de Polignac number, because 6130014764161 - 25 = 6130014764129 is a prime.
It is not a weakly prime, because it can be changed into another prime (6130015764161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3065007382080 + 3065007382081.
It is an arithmetic number, because the mean of its divisors is an integer number (3065007382081).
Almost surely, 26130014764161 is an apocalyptic number.
It is an amenable number.
6130014764161 is a deficient number, since it is larger than the sum of its proper divisors (1).
6130014764161 is an equidigital number, since it uses as much as digits as its factorization.
6130014764161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 40.
Adding to 6130014764161 its reverse (1614674100316), we get a palindrome (7744688864477).
The spelling of 6130014764161 in words is "six trillion, one hundred thirty billion, fourteen million, seven hundred sixty-four thousand, one hundred sixty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •