61309553986673 has 2 divisors, whose sum is σ = 61309553986674. Its totient is φ = 61309553986672.

The previous prime is 61309553986547. The next prime is 61309553986679. The reversal of 61309553986673 is 37668935590316.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50252545743409 + 11057008243264 = 7088903^2 + 3325208^2 .

It is a cyclic number.

It is not a de Polignac number, because 61309553986673 - 2¹⁴ = 61309553970289 is a prime.

It is a super-2 number, since 2×61309553986673² (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 61309553986597 and 61309553986606.

It is not a weakly prime, because it can be changed into another prime (61309553986679) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30654776993336 + 30654776993337.

It is an arithmetic number, because the mean of its divisors is an integer number (30654776993337).

Almost surely, 2^{61309553986673} is an apocalyptic number.

It is an amenable number.

61309553986673 is a deficient number, since it is larger than the sum of its proper divisors (1).

61309553986673 is an equidigital number, since it uses as much as digits as its factorization.

61309553986673 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 661348800, while the sum is 71.

The spelling of 61309553986673 in words is "sixty-one trillion, three hundred nine billion, five hundred fifty-three million, nine hundred eighty-six thousand, six hundred seventy-three".