Base | Representation |
---|---|
bin | 111001000110011101… |
… | …101111100000010001 |
3 | 12212020220212022020222 |
4 | 321012131233200101 |
5 | 2001031301302032 |
6 | 44055523242425 |
7 | 4300235140166 |
oct | 710635574021 |
9 | 185226768228 |
10 | 61311744017 |
11 | 24002976827 |
12 | ba71219415 |
13 | 5a21447794 |
14 | 2d78b9006d |
15 | 18dc9b2a12 |
hex | e4676f811 |
61311744017 has 2 divisors, whose sum is σ = 61311744018. Its totient is φ = 61311744016.
The previous prime is 61311743989. The next prime is 61311744041. The reversal of 61311744017 is 71044711316.
61311744017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45345147136 + 15966596881 = 212944^2 + 126359^2 .
It is a cyclic number.
It is not a de Polignac number, because 61311744017 - 26 = 61311743953 is a prime.
It is a super-2 number, since 2×613117440172 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (61311749017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30655872008 + 30655872009.
It is an arithmetic number, because the mean of its divisors is an integer number (30655872009).
Almost surely, 261311744017 is an apocalyptic number.
It is an amenable number.
61311744017 is a deficient number, since it is larger than the sum of its proper divisors (1).
61311744017 is an equidigital number, since it uses as much as digits as its factorization.
61311744017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14112, while the sum is 35.
The spelling of 61311744017 in words is "sixty-one billion, three hundred eleven million, seven hundred forty-four thousand, seventeen".
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