Base | Representation |
---|---|
bin | 101100100111000100111… |
… | …1111110101010011001011 |
3 | 210201010210012121021220120 |
4 | 1121032021333311103023 |
5 | 1300423231241341441 |
6 | 21012352205154323 |
7 | 1201652453140656 |
oct | 131161177652313 |
9 | 23633705537816 |
10 | 6131233543371 |
11 | 1a54272548a12 |
12 | 83033585b9a3 |
13 | 356232971841 |
14 | 172a7903a89d |
15 | a974a260966 |
hex | 59389ff54cb |
6131233543371 has 4 divisors (see below), whose sum is σ = 8174978057832. Its totient is φ = 4087489028912.
The previous prime is 6131233543297. The next prime is 6131233543399. The reversal of 6131233543371 is 1733453321316.
6131233543371 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 6131233543371 - 210 = 6131233542347 is a prime.
It is not an unprimeable number, because it can be changed into a prime (6131238543371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1021872257226 + ... + 1021872257231.
It is an arithmetic number, because the mean of its divisors is an integer number (2043744514458).
Almost surely, 26131233543371 is an apocalyptic number.
6131233543371 is a deficient number, since it is larger than the sum of its proper divisors (2043744514461).
6131233543371 is a wasteful number, since it uses less digits than its factorization.
6131233543371 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2043744514460.
The product of its digits is 408240, while the sum is 42.
Adding to 6131233543371 its reverse (1733453321316), we get a palindrome (7864686864687).
The spelling of 6131233543371 in words is "six trillion, one hundred thirty-one billion, two hundred thirty-three million, five hundred forty-three thousand, three hundred seventy-one".
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