Base | Representation |
---|---|
bin | 111001000111101001… |
… | …000100111000000001 |
3 | 12212022022000121212211 |
4 | 321013221010320001 |
5 | 2001101330223403 |
6 | 44101510422121 |
7 | 4300565040415 |
oct | 710751047001 |
9 | 185268017784 |
10 | 61331492353 |
11 | 24013034a6a |
12 | ba77961941 |
13 | 5a255704a1 |
14 | 2d7b650d45 |
15 | 18de5b406d |
hex | e47a44e01 |
61331492353 has 2 divisors, whose sum is σ = 61331492354. Its totient is φ = 61331492352.
The previous prime is 61331492303. The next prime is 61331492389. The reversal of 61331492353 is 35329413316.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37072806849 + 24258685504 = 192543^2 + 155752^2 .
It is a cyclic number.
It is not a de Polignac number, because 61331492353 - 217 = 61331361281 is a prime.
It is not a weakly prime, because it can be changed into another prime (61331492303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30665746176 + 30665746177.
It is an arithmetic number, because the mean of its divisors is an integer number (30665746177).
Almost surely, 261331492353 is an apocalyptic number.
It is an amenable number.
61331492353 is a deficient number, since it is larger than the sum of its proper divisors (1).
61331492353 is an equidigital number, since it uses as much as digits as its factorization.
61331492353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 174960, while the sum is 40.
The spelling of 61331492353 in words is "sixty-one billion, three hundred thirty-one million, four hundred ninety-two thousand, three hundred fifty-three".
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