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613659332081 is a prime number
BaseRepresentation
bin10001110111000001111…
…00100100110111110001
32011122221222022000112102
420323200330210313301
540023233242111311
61145524453110145
762223023154425
oct10734074446761
92148858260472
10613659332081
112172847709a4
129ab21328355
1345b387cca23
14219b63dcb85
1510e6910c43b
hex8ee0f24df1

613659332081 has 2 divisors, whose sum is σ = 613659332082. Its totient is φ = 613659332080.

The previous prime is 613659332057. The next prime is 613659332131. The reversal of 613659332081 is 180233956316.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 317739651856 + 295919680225 = 563684^2 + 543985^2 .

It is a cyclic number.

It is not a de Polignac number, because 613659332081 - 26 = 613659332017 is a prime.

It is a super-3 number, since 3×6136593320813 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (613659332281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306829666040 + 306829666041.

It is an arithmetic number, because the mean of its divisors is an integer number (306829666041).

Almost surely, 2613659332081 is an apocalyptic number.

It is an amenable number.

613659332081 is a deficient number, since it is larger than the sum of its proper divisors (1).

613659332081 is an equidigital number, since it uses as much as digits as its factorization.

613659332081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 699840, while the sum is 47.

The spelling of 613659332081 in words is "six hundred thirteen billion, six hundred fifty-nine million, three hundred thirty-two thousand, eighty-one".