Base | Representation |
---|---|
bin | 11011111011011100111000… |
… | …10101010100110011101011 |
3 | 22001110100100201222122202011 |
4 | 31331232130111110303223 |
5 | 31022221201202421301 |
6 | 334342141505020351 |
7 | 15636120442132003 |
oct | 1575563425246353 |
9 | 261410321878664 |
10 | 61416360201451 |
11 | 18629594237942 |
12 | 6a7aa9a9246b7 |
13 | 28366cba56c28 |
14 | 11247d3a79003 |
15 | 7178a9159a51 |
hex | 37db9c554ceb |
61416360201451 has 4 divisors (see below), whose sum is σ = 61899953588992. Its totient is φ = 60932766813912.
The previous prime is 61416360201439. The next prime is 61416360201473. The reversal of 61416360201451 is 15410206361416.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 61416360201451 - 27 = 61416360201323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (61416360201551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241796693580 + ... + 241796693833.
It is an arithmetic number, because the mean of its divisors is an integer number (15474988397248).
Almost surely, 261416360201451 is an apocalyptic number.
61416360201451 is a deficient number, since it is larger than the sum of its proper divisors (483593387541).
61416360201451 is a wasteful number, since it uses less digits than its factorization.
61416360201451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 483593387540.
The product of its (nonzero) digits is 103680, while the sum is 40.
Adding to 61416360201451 its reverse (15410206361416), we get a palindrome (76826566562867).
The spelling of 61416360201451 in words is "sixty-one trillion, four hundred sixteen billion, three hundred sixty million, two hundred one thousand, four hundred fifty-one".
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