Base | Representation |
---|---|
bin | 111001010100000001… |
… | …001000001101000001 |
3 | 12212211202201102000001 |
4 | 321110001020031001 |
5 | 2002013003432113 |
6 | 44134245000001 |
7 | 4305665631532 |
oct | 712401101501 |
9 | 185752642001 |
10 | 61539124033 |
11 | 2410a25a7a2 |
12 | bb153b3001 |
13 | 5a5959a37a |
14 | 2d9b05c689 |
15 | 19029297dd |
hex | e54048341 |
61539124033 has 2 divisors, whose sum is σ = 61539124034. Its totient is φ = 61539124032.
The previous prime is 61539124013. The next prime is 61539124081. The reversal of 61539124033 is 33042193516.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48473948224 + 13065175809 = 220168^2 + 114303^2 .
It is a cyclic number.
It is not a de Polignac number, because 61539124033 - 233 = 52949189441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 61539123983 and 61539124001.
It is not a weakly prime, because it can be changed into another prime (61539124013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30769562016 + 30769562017.
It is an arithmetic number, because the mean of its divisors is an integer number (30769562017).
Almost surely, 261539124033 is an apocalyptic number.
It is an amenable number.
61539124033 is a deficient number, since it is larger than the sum of its proper divisors (1).
61539124033 is an equidigital number, since it uses as much as digits as its factorization.
61539124033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 37.
The spelling of 61539124033 in words is "sixty-one billion, five hundred thirty-nine million, one hundred twenty-four thousand, thirty-three".
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