Base | Representation |
---|---|
bin | 11011111111001001101110… |
… | …11011001000110001111001 |
3 | 22001220111120110111221200202 |
4 | 31333210313123020301321 |
5 | 31031312110124320423 |
6 | 334520411232211545 |
7 | 15651241463514320 |
oct | 1577446733106171 |
9 | 261814513457622 |
10 | 61543516245113 |
11 | 18678505536531 |
12 | 6a9b667099bb5 |
13 | 28456b4680c56 |
14 | 112aa1755b0b7 |
15 | 71ad4c49e728 |
hex | 37f9376c8c79 |
61543516245113 has 8 divisors (see below), whose sum is σ = 70452477836160. Its totient is φ = 52663812328800.
The previous prime is 61543516245067. The next prime is 61543516245139. The reversal of 61543516245113 is 31154261534516.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 61543516245113 - 28 = 61543516244857 is a prime.
It is not an unprimeable number, because it can be changed into a prime (61543516245173) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7314414173 + ... + 7314422586.
It is an arithmetic number, because the mean of its divisors is an integer number (8806559729520).
Almost surely, 261543516245113 is an apocalyptic number.
It is an amenable number.
61543516245113 is a deficient number, since it is larger than the sum of its proper divisors (8908961591047).
61543516245113 is a wasteful number, since it uses less digits than its factorization.
61543516245113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14628837367.
The product of its digits is 1296000, while the sum is 47.
Adding to 61543516245113 its reverse (31154261534516), we get a palindrome (92697777779629).
The spelling of 61543516245113 in words is "sixty-one trillion, five hundred forty-three billion, five hundred sixteen million, two hundred forty-five thousand, one hundred thirteen".
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