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61712281353497 = 136145343336777
BaseRepresentation
bin11100000100000100000101…
…00110111011110100011001
322002111122011222211201222112
432002002002212323310121
531042043223011302442
6335130121454202105
715666364601333345
oct1602020246736431
9262448158751875
1061712281353497
1118733038a96315
126b083061b3335
13285859b818228
141134c671c0625
157204286bb082
hex3820829bbd19

61712281353497 has 4 divisors (see below), whose sum is σ = 61757624691636. Its totient is φ = 61666938015360.

The previous prime is 61712281353469. The next prime is 61712281353559. The reversal of 61712281353497 is 79435318221716.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4614853464841 + 57097427888656 = 2148221^2 + 7556284^2 .

It is a cyclic number.

It is not a de Polignac number, because 61712281353497 - 216 = 61712281287961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (61712281353427) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22671667028 + ... + 22671669749.

It is an arithmetic number, because the mean of its divisors is an integer number (15439406172909).

Almost surely, 261712281353497 is an apocalyptic number.

It is an amenable number.

61712281353497 is a deficient number, since it is larger than the sum of its proper divisors (45343338139).

61712281353497 is a wasteful number, since it uses less digits than its factorization.

61712281353497 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45343338138.

The product of its digits is 15240960, while the sum is 59.

The spelling of 61712281353497 in words is "sixty-one trillion, seven hundred twelve billion, two hundred eighty-one million, three hundred fifty-three thousand, four hundred ninety-seven".

Divisors: 1 1361 45343336777 61712281353497