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625401323 is a prime number
BaseRepresentation
bin100101010001101…
…101110111101011
31121120210200022222
4211101231313223
52240100320243
6142020304255
721332552321
oct4521556753
91546720288
10625401323
112a10282a8
1215554208b
139c750671
145d0b9d11
1539d89168
hex2546ddeb

625401323 has 2 divisors, whose sum is σ = 625401324. Its totient is φ = 625401322.

The previous prime is 625401319. The next prime is 625401353. The reversal of 625401323 is 323104526.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 625401323 - 22 = 625401319 is a prime.

It is a super-2 number, since 2×6254013232 = 782253629620300658, which contains 22 as substring.

It is equal to p32580008 and since 625401323 and 32580008 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 625401292 and 625401301.

It is not a weakly prime, because it can be changed into another prime (625401313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 312700661 + 312700662.

It is an arithmetic number, because the mean of its divisors is an integer number (312700662).

Almost surely, 2625401323 is an apocalyptic number.

625401323 is a deficient number, since it is larger than the sum of its proper divisors (1).

625401323 is an equidigital number, since it uses as much as digits as its factorization.

625401323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 26.

The square root of 625401323 is about 25008.0251719323. The cubic root of 625401323 is about 855.1709348969.

Adding to 625401323 its reverse (323104526), we get a palindrome (948505849).

The spelling of 625401323 in words is "six hundred twenty-five million, four hundred one thousand, three hundred twenty-three".