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630544153 is a prime number
BaseRepresentation
bin100101100101010…
…101011100011001
31121221110221222011
4211211111130121
52242404403103
6142322425521
721424352101
oct4545253431
91557427864
10630544153
112a3a20178
121572022a1
13a0831465
145da58201
153a552d6d
hex25955719

630544153 has 2 divisors, whose sum is σ = 630544154. Its totient is φ = 630544152.

The previous prime is 630544141. The next prime is 630544163. The reversal of 630544153 is 351445036.

630544153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 476461584 + 154082569 = 21828^2 + 12413^2 .

It is a cyclic number.

It is not a de Polignac number, because 630544153 - 217 = 630413081 is a prime.

It is not a weakly prime, because it can be changed into another prime (630544163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 315272076 + 315272077.

It is an arithmetic number, because the mean of its divisors is an integer number (315272077).

Almost surely, 2630544153 is an apocalyptic number.

It is an amenable number.

630544153 is a deficient number, since it is larger than the sum of its proper divisors (1).

630544153 is an equidigital number, since it uses as much as digits as its factorization.

630544153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

The square root of 630544153 is about 25110.6382435811. The cubic root of 630544153 is about 857.5086328806.

Adding to 630544153 its reverse (351445036), we get a palindrome (981989189).

The spelling of 630544153 in words is "six hundred thirty million, five hundred forty-four thousand, one hundred fifty-three".