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63134401513 = 136746184639
BaseRepresentation
bin111010110011000110…
…101000001111101001
320000221221111220022011
4322303012220033221
52013244401322023
645000433155521
74363346362351
oct726306501751
9200857456264
1063134401513
11248587a6337
121029b6bbba1
135c51c3b741
1430acc83b61
1519979e450d
hexeb31a83e9

63134401513 has 4 divisors (see below), whose sum is σ = 63180587520. Its totient is φ = 63088215508.

The previous prime is 63134401493. The next prime is 63134401531. The reversal of 63134401513 is 31510443136.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 63134401513 - 213 = 63134393321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (63134401553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23090953 + ... + 23093686.

It is an arithmetic number, because the mean of its divisors is an integer number (15795146880).

Almost surely, 263134401513 is an apocalyptic number.

It is an amenable number.

63134401513 is a deficient number, since it is larger than the sum of its proper divisors (46186007).

63134401513 is a wasteful number, since it uses less digits than its factorization.

63134401513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46186006.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 63134401513 its reverse (31510443136), we get a palindrome (94644844649).

The spelling of 63134401513 in words is "sixty-three billion, one hundred thirty-four million, four hundred one thousand, five hundred thirteen".

Divisors: 1 1367 46184639 63134401513