Base | Representation |
---|---|
bin | 101101111100101001110… |
… | …0110000010010010110001 |
3 | 211100201010111220022201211 |
4 | 1123321103212002102301 |
5 | 1311431112111424123 |
6 | 21233023432400121 |
7 | 1221146460530341 |
oct | 133712346022261 |
9 | 24321114808654 |
10 | 6315004404913 |
11 | 20151a639a196 |
12 | 85ba82246041 |
13 | 36a66b8ba6b9 |
14 | 17b90d980d21 |
15 | ae403a2b40d |
hex | 5be539824b1 |
6315004404913 has 2 divisors, whose sum is σ = 6315004404914. Its totient is φ = 6315004404912.
The previous prime is 6315004404881. The next prime is 6315004404991. The reversal of 6315004404913 is 3194044005136.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6170713064464 + 144291340449 = 2484092^2 + 379857^2 .
It is a cyclic number.
It is not a de Polignac number, because 6315004404913 - 25 = 6315004404881 is a prime.
It is not a weakly prime, because it can be changed into another prime (6315004404013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3157502202456 + 3157502202457.
It is an arithmetic number, because the mean of its divisors is an integer number (3157502202457).
Almost surely, 26315004404913 is an apocalyptic number.
It is an amenable number.
6315004404913 is a deficient number, since it is larger than the sum of its proper divisors (1).
6315004404913 is an equidigital number, since it uses as much as digits as its factorization.
6315004404913 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 6315004404913 in words is "six trillion, three hundred fifteen billion, four million, four hundred four thousand, nine hundred thirteen".
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