Base | Representation |
---|---|
bin | 101101111101010011011… |
… | …0110111011111100111101 |
3 | 211100211201212111012100021 |
4 | 1123322212312323330331 |
5 | 1311441442221004232 |
6 | 21233414213532141 |
7 | 1221226212365101 |
oct | 133724666737475 |
9 | 24324655435307 |
10 | 6316401344317 |
11 | 2015852988469 |
12 | 8601b2044051 |
13 | 36a83213706c |
14 | 17ba032d7901 |
15 | ae4864b9397 |
hex | 5bea6dbbf3d |
6316401344317 has 16 divisors (see below), whose sum is σ = 6485946888960. Its totient is φ = 6147889336512.
The previous prime is 6316401344291. The next prime is 6316401344321. The reversal of 6316401344317 is 7134431046136.
It is a cyclic number.
It is not a de Polignac number, because 6316401344317 - 211 = 6316401342269 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6316401344017) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 226226284 + ... + 226254202.
It is an arithmetic number, because the mean of its divisors is an integer number (405371680560).
Almost surely, 26316401344317 is an apocalyptic number.
It is an amenable number.
6316401344317 is a deficient number, since it is larger than the sum of its proper divisors (169545544643).
6316401344317 is a wasteful number, since it uses less digits than its factorization.
6316401344317 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46212.
The product of its (nonzero) digits is 435456, while the sum is 43.
The spelling of 6316401344317 in words is "six trillion, three hundred sixteen billion, four hundred one million, three hundred forty-four thousand, three hundred seventeen".
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